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1 如圖甲乙丙句股形 取甲乙句三分之一於丁乙丙股三分之一於戊各作線己丁庚戊交點心 即句股面重心因庚戊過心點正交乙丙己丁過心點正交甲乙故取庚己 二點懸之股與句必皆平於地平又因丁己為句三分之一乙戊為股三 分之一故己丙甲庚必均為弦三分之一
URN: ctp:ws496529

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